Work Calculator
Calculate work done, applied force, or displacement using W = F·d·cos(θ). Includes angle adjustment for forces not parallel to motion.
What Is Work in Physics?
In physics, work has a precise meaning distinct from everyday usage. Work is done when a force causes displacement in the direction of that force. The formula is W = F·d·cos(θ), where F is the magnitude of the applied force (N), d is the displacement (m), and θ is the angle between the force vector and the direction of motion. The SI unit is the joule (J) — equal to one newton-meter (N·m).
The cosine factor is critical and often overlooked. Only the component of force in the direction of motion does work. Push a box at 30° to the floor: only F·cos(30°) contributes to horizontal displacement. At θ = 90° (force perpendicular to motion), cos(90°) = 0 — no work is done. This is why a person carrying a heavy box horizontally across a room does zero work against gravity: the carrying force is vertical while displacement is horizontal.
Work can be negative. Friction opposes motion (θ = 180°, cos = −1), so friction always does negative work, removing energy from the system. Gravity does negative work when you lift an object but positive work when it falls.
The work-energy theorem states that the net work done on an object equals its change in kinetic energy: W_net = ΔKE = ½mv_f² − ½mv_i². This powerful principle allows you to find the velocity of an object after a force acts over a distance, even without knowing time. And the work-power relationship connects work to the rate at which it is done: P = W/t (power equals work per unit time).
Formula Reference Table
| Solve For | Formula | Notes |
|---|---|---|
| Work (W) | W = F · d · cos θ | θ = angle between force and displacement |
| Force (F) | F = W / (d · cos θ) | Requires cos θ ≠ 0 (θ ≠ 90°) |
| Distance (d) | d = W / (F · cos θ) | Displacement in direction of motion |
| Work-Energy Theorem | W_net = ΔKE = ½mv_f² − ½mv_i² | Net work = change in KE |
| Work by gravity | W_gravity = mgh | Positive when falling (h > 0) |
| Work by spring | W_spring = ½kx² | Energy stored in spring |
3 Worked Examples
A person pushes a 20 kg box with 150 N at 25° below horizontal, moving it 8 m. How much work is done?
- Effective horizontal force: F_x = 150 × cos(25°) = 150 × 0.906 = 135.9 N
- Work: W = F · d · cos θ = 150 × 8 × cos(25°) = 1,087 J
- Note: The vertical component (150 × sin25° = 63.4 N) presses into the floor — does no work on horizontal motion
A 5 kg object starts at rest. A net force of 40 N acts over 3 m. What is the final speed?
- Net work: W = F × d = 40 × 3 = 120 J (θ = 0°, force parallel to motion)
- Work-energy theorem: W = ½mv_f² − 0 → 120 = ½ × 5 × v_f²
- Solve: v_f² = 240/5 = 48 → v_f = √48 = 6.93 m/s
A 70 kg person carries a 15 kg box 50 m horizontally. How much work is done against gravity?
- Gravity force: F_g = mg = 15 × 9.8 = 147 N (downward)
- Displacement: 50 m horizontal (rightward)
- Angle between force and displacement: θ = 90°, cos(90°) = 0
- Work by gravity: W = 147 × 50 × 0 = 0 J
- The person's muscles do work against their own body (vertical oscillations), but gravity does zero work
Real-World Applications
Common Mistakes to Avoid
If you push at 30° and use W = Fd, you overestimate work by 1/cos(30°) ≈ 15%. Always resolve the force into the component parallel to displacement, or use the cosine factor explicitly.
Work (J) is energy transferred. Force (N) is what causes acceleration. A force can exist without doing work (a wall holding up a shelf exerts force but does zero work since d = 0). Work requires both force and displacement in the same direction.
Work W = Fd is independent of how long the force acts. Whether you push a box 10 m in 1 second or 10 minutes, the work done is identical. Time matters for power (P = W/t), not work.
Work can be negative (friction, gravity during lift). When using the work-energy theorem, you must sum all work including negative contributions. Friction's negative work reduces final kinetic energy.
Work uses displacement (straight-line distance from start to finish), not total path length. A person who walks 100 m along a curved path and ends 20 m from the start has displacement = 20 m (for work against friction, use path length, but for gravity, use vertical height change).
Frequently Asked Questions
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Interpretation: This relationship connects motion, force, momentum, work or energy in a mechanical system. Assumption: Choose a consistent reference direction and unit system. The model may assume constant acceleration, rigid bodies, negligible losses or an isolated system.