Potential Energy Calculator
Calculate gravitational potential energy, mass, or height using PE = mgh. Supports all common units with instant conversion.
What Is Potential Energy?
Potential energy (PE) is stored energy that an object possesses due to its position or configuration relative to other objects. Unlike kinetic energy, which is energy of motion, potential energy represents the capacity to do work — it hasn't been converted to motion yet, but it will be when conditions allow.
The most common form in introductory physics is gravitational potential energy, given by PE = mgh, where m is mass (kg), g is gravitational acceleration (9.8 m/s² on Earth), and h is height above a reference level (m). The reference level is arbitrary — you choose it. Often the ground, the table surface, or the lowest point of the problem is set as h = 0.
A second important form is elastic potential energy (stored in springs and elastic materials): PE_elastic = ½kx², where k is the spring constant and x is the compression or extension from equilibrium. This formula mirrors the kinetic energy equation KE = ½mv².
The power of potential energy comes from the law of conservation of mechanical energy: in the absence of friction and other dissipative forces, the total mechanical energy (KE + PE) remains constant throughout motion. This is why a roller coaster car at the top of a hill (maximum PE, minimum KE) moves fastest at the bottom (minimum PE, maximum KE) — the energy simply changes form. Knowing PE at any height instantly gives you the velocity anywhere else on the track.
Formula Reference Table
| Form | Formula | Variables | SI Unit |
|---|---|---|---|
| Gravitational PE | PE = m·g·h | m = mass, g = 9.8 m/s², h = height | J |
| Find Mass | m = PE / (g·h) | PE = energy, h = height | kg |
| Find Height | h = PE / (m·g) | PE = energy, m = mass | m |
| Elastic PE (spring) | PE = ½·k·x² | k = spring constant, x = displacement | J |
| Conservation of Energy | PE₁ + KE₁ = PE₂ + KE₂ | At any two points in the system | J |
| Velocity from PE drop | v = √(2gh) | When KE₁ = 0 (starts at rest) | m/s |
3 Worked Examples
A 70 kg person stands at the edge of a 45-meter cliff. What is their gravitational PE relative to the base?
- Given: m = 70 kg, g = 9.8 m/s², h = 45 m
- Apply: PE = m × g × h = 70 × 9.8 × 45
- Result: PE = 30,870 J = 30.87 kJ
A coaster car (500 kg) starts from rest at 40 m height. Ignoring friction, what is its speed at the bottom?
- At top: PE = mgh = 500 × 9.8 × 40 = 196,000 J; KE = 0
- Conservation: Total energy = 196,000 J at all points
- At bottom: h = 0, so PE = 0; all energy is KE = ½mv²
- Solve for v: v = √(2gh) = √(2 × 9.8 × 40) = √784 = 28 m/s
A water tank stores 5 × 10⁷ J of gravitational PE at a height of 25 m. What mass of water does it hold?
- Rearrange: m = PE / (g × h)
- Substitute: m = (5 × 10⁷) / (9.8 × 25)
- Calculate: m = 5 × 10⁷ / 245 = 204,082 kg ≈ 204 tonnes
- At 1 kg/L, that's ≈ 204,000 litres of water
Real-World Applications
Common Mistakes to Avoid
PE is always relative to a chosen zero height. If you set h = 0 at the ground for one object but at the table for another in the same problem, your energy comparisons will be wrong. Pick one reference and stick to it throughout.
PE = mgh requires m in kg, g in m/s², and h in meters to get joules. Using grams for mass or feet for height without conversion produces wrong answers — often by factors of 1,000 or more.
Weight (W = mg) is force in newtons; potential energy (PE = mgh) is energy in joules. They share the factors m and g but are different quantities with different units and physical meanings.
PE + KE = constant only when there are no non-conservative forces (like friction or air resistance). In real problems, energy is lost to heat: PE₁ + KE₁ = PE₂ + KE₂ + E_loss.
g = 10 is a useful approximation for mental math, but it introduces a 2% error. In exam problems and engineering calculations, use g = 9.8 m/s² (or 9.81 m/s² for higher precision).
PE can be negative if h is measured below the reference level (e.g., a mine shaft below ground level). This is physically valid — it just means the object would need to gain PE to reach the reference point.
Frequently Asked Questions
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Formula Explorer connections
Interpretation: This relationship connects motion, force, momentum, work or energy in a mechanical system. Assumption: Choose a consistent reference direction and unit system. The model may assume constant acceleration, rigid bodies, negligible losses or an isolated system.