Half-Life Calculator
Calculate remaining quantity, half-life, or elapsed time using N = N₀·(½)^(t/t½).
What Is Half-Life?
The half-life (t½) is the time for exactly half of a radioactive sample to decay. After one half-life: 50% remains. After two: 25%. After n half-lives: N = N₀ × (½)ⁿ = N₀ × (½)^(t/t½). This exponential decay applies to radioactive nuclei, drug concentrations in the body, and any first-order process.
Half-lives span enormous ranges: polonium-214: 164 μs; radon-222: 3.8 days; carbon-14: 5,730 years; uranium-238: 4.47 billion years (comparable to Earth's age). The decay constant λ = ln(2)/t½ = 0.693/t½ connects the half-life to the more fundamental exponential form N = N₀e^(−λt).
Radiocarbon dating uses C-14 (t½ = 5,730 years) to date organic materials up to ~50,000 years old. Living organisms maintain a constant C-14/C-12 ratio (from atmospheric CO₂). After death, C-14 decays. Measuring the remaining ratio gives the time since death: t = (t½/ln2) × ln(N₀/N).
Activity (A) is the decay rate: A = λN = (ln2/t½) × N, measured in Becquerels (Bq; 1 Bq = 1 decay/s) or Curies (Ci; 1 Ci = 3.7×10¹⁰ Bq). Both N (quantity) and A (activity) halve with each half-life. A 1 GBq sample becomes 0.5 GBq after one half-life.
Formula Reference Table
| Solve For | Formula | Notes |
|---|---|---|
| Remaining quantity | N = N₀ × (½)^(t/t½) | Same units as N₀ |
| Exponential form | N = N₀ · e^(−λt) | λ = ln(2)/t½ = 0.693/t½ |
| Number of half-lives | n = t/t½ | N = N₀/2ⁿ |
| Time elapsed | t = t½ · log₂(N₀/N) | = t½·ln(N₀/N)/ln2 |
| Half-life from λ | t½ = ln(2)/λ = 0.693/λ | λ = decay constant (s⁻¹) |
| Activity | A = λN = N·ln(2)/t½ | Bq (decays/s) or Ci |
3 Worked Examples
A bone fragment has C-14 activity 25% of a living sample. t½(C-14) = 5,730 yr.
- N/N₀ = 0.25 = (½)^(t/5730)
- t/5730 = log₂(1/0.25) = log₂(4) = 2
- t = 2 × 5,730 = 11,460 years old
Tc-99m: t½ = 6.02 hr. Patient receives 500 MBq. Activity after 24 hr?
- n = 24/6.02 = 3.99 ≈ 4 half-lives
- A = 500 × (½)⁴ = 500/16 = 31.25 MBq
- After 48 hr: 500/256 = 1.95 MBq (safe to discharge patient)
Strontium-90 (t½ = 28.8 yr). How long until 1,000 g decays to 1 g?
- N/N₀ = 1/1000 = 0.001
- n = log₂(1000) = 9.97 half-lives
- t = 9.97 × 28.8 = 287 years
Real-World Applications
Common Mistakes to Avoid
Mean lifetime τ = t½/ln(2) = 1.443 × t½. After one mean lifetime, 1/e ≈ 36.8% remains (not 50%). After one half-life, exactly 50% remains.
N = N₀(½)^(t/t½) uses base ½. The equivalent N = N₀e^(−λt) uses natural log and λ = ln2/t½. Don't mix: N₀e^(−t/t½) gives wrong result (uses wrong base).
t and t½ must be in the same units. If t½ = 5,730 years and t = 11,460 years, n = 2. If one is in years and the other in days, convert first.
Both N (atoms/grams) and activity A = λN halve every half-life. But A depends on λ too: a short-lived isotope with large λ has high activity even with few atoms.
In 2 half-lives: 25% remains, not 0%. In 10 half-lives: (½)¹⁰ = 0.098% remains. True zero is never reached mathematically — only approached asymptotically.
Frequently Asked Questions
Related Physics Calculators
Formula Explorer connections
Interpretation: This relationship connects quantized energy, wavelength, probability, nuclear mass or radioactive change. Assumption: Use the correct particle, quantum state, nuclide and energy units. Idealized potentials, nonrelativistic motion or single decay channels may be assumed.