Pair Production Calculator

Pair production converts a photon into an electron-positron pair. The photon must have energy above 1.022 MeV (threshold). This is one of the ways high-energy photons interact with matter.

⚛️ Quantum Physics📐 E = 2mᵉc²☢️ Nuclear Physics
Photon Energy (MeV)
Or Wavelength (pm)
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How a photon turns into matter

Pair production is the conversion of a photon into an electron–positron pair. It is the cleanest demonstration of E = mc² running in reverse: pure energy becoming rest mass.

It cannot happen in empty space. A lone photon has energy E and momentum E/c; an electron–positron pair created at rest would have energy 2mₑc² and zero momentum. No reference frame makes both conserve at once. A nearby heavy nucleus absorbs the excess momentum (taking almost no energy, because it is thousands of times heavier), which is why pair production always occurs in matter.

That nuclear dependence has a practical consequence: the probability scales roughly as Z², so lead shields against high-energy gamma rays far more effectively than aluminium of the same mass.

Formula Reference Table

Ethreshold = 2mₑc² = 1.022 MeV   ·   KEtotal = Ephoton − 1.022 MeV
SymbolMeaning
E_photonenergy of the incoming gamma ray (MeV)
mₑc²electron rest energy = 0.511 MeV
KE_totalkinetic energy shared between the electron and positron
λ_thresholdhc / E = 1.213 × 10⁻¹² m — the longest wavelength that can do it

In the field of an atomic electron rather than a nucleus, the recoiling electron is light and carries off real energy, pushing the threshold to 4mₑc² = 2.044 MeV. This variant is called triplet production.

3 Worked Examples

Example 1
Kinetic energy from a 2.00 MeV photon

A 2.00 MeV gamma ray undergoes pair production near a lead nucleus. How much kinetic energy do the electron and positron share?

  • Check threshold: 2.00 MeV > 1.022 MeV ✓ — the process is allowed
  • KE_total = E_photon − 2mₑc² = 2.00 − 1.022
  • KE_total = 0.978 MeV
  • If shared equally: 0.978 / 2 = 0.489 MeV each
0.978 MeV total, ≈ 0.489 MeV each

Equal sharing is the average case, not a rule. The split varies event to event; the positron tends to run slightly faster because the nucleus repels it and attracts the electron.

Example 2
Threshold wavelength

What is the longest wavelength of light that can produce an electron–positron pair?

  • Use E = hc/λ, so λ = hc / E
  • hc = 1239.84 eV·nm, E = 1.022 × 10⁶ eV
  • λ = 1239.84 / 1.022 × 10⁶ = 1.213 × 10⁻³ nm
λ ≈ 1.213 × 10⁻¹² m (1.213 pm) — deep in the gamma-ray band

For comparison, visible light is around 5 × 10⁻⁷ m — roughly 400,000 times too long. Nothing below gamma energies can do this.

Example 3
How fast do the particles move?

A 5.00 MeV photon produces a pair that shares kinetic energy equally. Find the speed of each particle.

  • KE_total = 5.00 − 1.022 = 3.978 MeV, so KE each = 1.989 MeV
  • Total energy of each: E = KE + mₑc² = 1.989 + 0.511 = 2.50 MeV
  • Lorentz factor γ = E / mₑc² = 2.50 / 0.511 = 4.892
  • v/c = √(1 − 1/γ²) = √(1 − 1/23.93) = √0.9582
v ≈ 0.979c — about 2.94 × 10⁸ m/s

Classical KE = ½mv² would give a nonsense answer above c here. Above roughly 0.1 MeV of kinetic energy for an electron, you must use the relativistic form.

Key values

QuantityValue
Electron / positron rest energy0.51099895 MeV
Pair production threshold (nuclear field)1.022 MeV
Triplet production threshold (electron field)2.044 MeV
Threshold wavelength1.2132 × 10⁻¹² m
Threshold frequency2.471 × 10²⁰ Hz
hc (convenient form)1239.84 eV·nm

Which photon interaction dominates

Photon energyDominant processNotes
< 100 keVPhotoelectric absorptionStrong Z dependence (≈ Z⁴⁻⁵); basis of X-ray contrast
100 keV – 1 MeVCompton scatteringNearly Z-independent per electron; dominates in soft tissue
1.022 – 5 MeVCompton, with pair production opening upPair production begins but is still a minority channel
> 5 MeV in high-Z materialPair productionScales as Z²; dominant in lead above ≈ 5 MeV
> 10 MeVPair production strongly dominantDrives electromagnetic showers in calorimeters

The crossover energies shift with atomic number: in water pair production only takes over above roughly 25 MeV, in lead above about 5 MeV.

Kinetic energy released at common photon energies

Photon energyKE totalKE each (equal split)
1.022 MeV0 MeVPair created at rest — threshold exactly
1.50 MeV0.478 MeV0.239 MeV
2.00 MeV0.978 MeV0.489 MeV
5.00 MeV3.978 MeV1.989 MeV
10.0 MeV8.978 MeV4.489 MeV

Common Mistakes to Avoid

⚠️
Forgetting there are two particles

The threshold is 2mₑc² = 1.022 MeV, not 0.511 MeV. A photon of 0.75 MeV has plenty of energy for one electron and still cannot produce a pair.

⚠️
Ignoring the nucleus

Pair production in a vacuum is forbidden by momentum conservation. Exam questions often ask why — the answer is that a third body is required to absorb momentum, and it must be heavy so it takes negligible energy.

⚠️
Using classical kinetic energy

At these energies the particles are relativistic. Use E = γmc² and KE = (γ − 1)mc². Plugging into ½mv² will give speeds above c.

⚠️
Assuming an exact 50/50 energy split

Equal sharing is the mean, not the outcome of any individual event. The distribution is broad and slightly asymmetric because of the Coulomb field of the nucleus.

Frequently Asked Questions

Why is the threshold 1.022 MeV?
Because two particles are created, each with rest energy 0.511 MeV. The photon must supply at least the combined rest mass, 2 × 0.511 = 1.022 MeV. Any energy above that becomes kinetic energy of the pair.
Why can't pair production happen in a vacuum?
Energy and momentum cannot both be conserved. A photon of energy E carries momentum E/c. In the frame where the created pair has zero total momentum, the photon would need zero momentum too — impossible for a real photon. A nearby nucleus absorbs the momentum imbalance while taking almost no energy because of its large mass.
What happens to the positron afterwards?
It slows down through collisions in the surrounding material, then annihilates with an ordinary electron. That annihilation typically produces two 0.511 MeV photons emitted back-to-back — the signal that PET scanners are built to detect.
Does the atomic number of the material matter?
Considerably. The cross-section scales roughly as Z², so lead (Z = 82) is dramatically more effective than aluminium (Z = 13) at the same areal density. This is the main reason high-energy gamma shielding uses lead or tungsten.
What is triplet production?
Pair production in the field of an atomic electron rather than a nucleus. Because the recoiling electron is light, it carries away real kinetic energy, raising the threshold to 4mₑc² = 2.044 MeV. Three particles emerge — two electrons and a positron — hence the name.
Can other particle–antiparticle pairs be produced?
Yes, given enough energy. Muon pairs need 2 × 105.7 = 211.3 MeV; proton–antiproton pairs need 2 × 938.3 = 1876.6 MeV. Electron–positron pairs are simply the cheapest, which is why they dominate at accessible gamma energies.
How does this relate to electromagnetic showers?
A high-energy photon pair-produces; the electron and positron then emit bremsstrahlung photons; those photons pair-produce again. The cascade doubles roughly every radiation length until the particles drop below 1.022 MeV. This is the operating principle of electromagnetic calorimeters in particle detectors.
Is pair production the reverse of annihilation?
Physically yes — it is the same vertex read in the opposite time direction. The practical difference is the threshold: annihilation happens at any energy, including at rest, while production requires at least 1.022 MeV plus a third body to take up momentum.

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Formula Explorer connections

Interpretation: This relationship connects quantized energy, wavelength, probability, nuclear mass or radioactive change. Assumption: Use the correct particle, quantum state, nuclide and energy units. Idealized potentials, nonrelativistic motion or single decay channels may be assumed.

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