Lattice Energy Calculator
Calculate lattice energy of ionic compounds using the Born-Haber cycle or Kapustinskii equation. Estimate lattice energy from ionic charges and radii for any ionic compound.
Formula & Reference
| Variable | Symbol | Formula | Units |
|---|---|---|---|
| Lattice Energy Calculator | — | U = k(Q+Q-)/(r+ + r-) | kJ/mol |
Step-by-Step Examples
Na+: Q+=1, r+=102 pm. Cl-: Q-=1, r-=181 pm. n=1.
- U = 1202 x 1 x (1x1)/(102+181) = 1202/283 = 4.25 x 1000/283
- = 1202000/283 ~ 4247 is wrong; use U = 1202*n*Q+Q-/(r+r-)
- U = 1202 x 1 x 1 / (0.102+0.181 nm)
- Wait: formula uses nm. r(nm)=(102+181)/1000=0.283 nm
- U = 1202/0.283 = 4248 kJ/mol
Mg2+: Q+=2, r+=72 pm. O2-: Q-=2, r-=140 pm. n=1.
- Charges doubled from NaCl: Q+Q- = 4x NaCl
- r(sum) = 212 pm < 283 pm for NaCl
- U much larger for MgO: ~3800 kJ/mol
Known values: dHf(NaCl)=-411, Sub(Na)=+107, IE1(Na)=+496, dHf(Cl)=+122, EA(Cl)=-349.
- U = dHf - Sub - IE1 - dHf(Cl) - EA
- = -411 - 107 - 496 - 122 - (-349) = -787 kJ/mol
Real-World Applications
Common Mistakes to Avoid
Convention: lattice energy = energy to separate ion pair = positive. Some books define as negative (formation from ions).
Doubling both charges (NaCl vs MgO) quadruples lattice energy (2x2=4). Hence MgO (3800) vs NaCl (787) kJ/mol.
Smaller r+ + r- increases U. LiF (high U: small ions) vs CsI (low U: large ions).
Frequently Asked Questions
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Formula Explorer connections
Interpretation: This relationship tracks energy transfer, state-function change or the balance between enthalpy and entropy in a chemical process. Assumption: Keep energy units compatible, use kelvin for absolute temperature, and match standard states and reaction stoichiometry. Thermodynamic favorability does not determine reaction speed.