Specific Heat Calculator

Calculate specific heat capacity from calorimetry data c = q divided by m times delta T. Identify unknown metals by comparing to known values. Solve for q, m, or delta T.

🌡️ Thermochemistry📐 c = q/(mΔT)🧪 Chemistry
Heat q (J)
Mass m (g)
Temperature change ΔT (°C)
Please enter valid values.

Formula & Reference

VariableSymbolFormulaUnits
Specific Heat CalculatorSee formulac = q/(mΔT)J/g·°C

Step-by-Step Examples

Example 1
Identify Metal

Hot metal (150 g) drops from 100 C into 200 g water at 25 C. Final T = 27.8 C.

  • q(water) = 200x4.184x2.8 = 2343 J absorbed
  • q(metal) = -2343 J (heat released by metal)
  • c(metal) = 2343/(150x72.2) = 0.216 J/g-C
  • Closest match: Silver (0.235) or Tin (0.228)
✓ c ~ 0.216 J/g-C (likely silver or tin)
Example 2
Alloy Sample

500 J heats 50 g alloy sample by 20.0 C.

  • c = 500/(50x20.0) = 0.500 J/g-C
✓ c = 0.500 J/g-C
Example 3
Temperature Rise

200 g water, q = 4184 J added. What is delta-T?

  • q = mcdT: 4184 = 200x4.184xdT
  • dT = 4184/836.8 = 5.00 C
✓ Delta-T = 5.00 C

Real-World Applications

🌡️
Metal Identification
Specific heat is characteristic of each metal; allows identification from calorimetry.
🏭
Heat Management
Engineering cooling systems requires knowing specific heat of materials.
🍿
Food Technology
Specific heat of foods determines heating and cooling times in processing.
☀️
Solar Thermal
High specific heat materials (water, molten salt) store solar energy efficiently.

Common Mistakes to Avoid

⚠️
Heat lost by metal = heat gained by water

In metal identification: q(metal) = -q(water). Metal loses heat; water gains it. Sign flip is critical.

⚠️
Mass of substance being characterized

c = q/(mxdT) where m is the mass of the sample whose specific heat you want.

⚠️
Sign of dT

If substance cooled: dT negative. If heated: dT positive. Consistent signs throughout.

Frequently Asked Questions

What are specific heats of common substances?
Water: 4.184, ethanol: 2.44, ice: 2.09, aluminum: 0.900, iron: 0.449, copper: 0.385, gold: 0.129 J/g-C.
Why does water have such high specific heat?
Strong hydrogen bonding requires lots of energy to speed up molecular motion. Also, small molecule mass means many molecules per gram.
What is Dulong-Petit Law?
For solid metals, molar heat capacity ~ 3R = 24.9 J/mol-C. So c ~ 25/M. Works well for heavy metals at room temperature.
How do I find specific heat experimentally?
Heat metal to known T, drop in water, measure final T. q(metal)=-q(water): m1c1(Tf-Ti1) = -m2c2(Tf-Ti2). Solve for c1.
What is heat capacity of a calorimeter?
Calorimeter absorbs some heat. Coffee cup: assumed negligible. Bomb calorimeter: calibrated by known combustion. Must include in precise work.

Related Chemistry Calculators

Formula Explorer connections

Interpretation: This relationship tracks energy transfer, state-function change or the balance between enthalpy and entropy in a chemical process. Assumption: Keep energy units compatible, use kelvin for absolute temperature, and match standard states and reaction stoichiometry. Thermodynamic favorability does not determine reaction speed.

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