Kp to Kc Calculator

Convert between Kp (pressure-based) and Kc (concentration-based) equilibrium constants using Kp = Kc*(RT)^(delta-n). Find delta-n from the balanced equation.

⚖️ Equilibrium📐 Kp = Kc(RT)Δn🧪 Chemistry
Kc or Kp (value to convert from)
Δn (moles gas products - reactants)
Temperature T (K)
Convert direction
Please enter valid values.

Formula & Reference

VariableSymbolFormulaUnits
Kp to Kc CalculatorSee formulaKp = Kc(RT)Δndimensionless

Step-by-Step Examples

Example 1
N2+3H2 to 2NH3

delta-n = 2-4 = -2. Kc=6.02 at 500 K. Find Kp.

  • Kp = Kc(RT)^delta-n
  • Kp = 6.02 x (0.08206x500)^(-2)
  • Kp = 6.02 x (41.03)^(-2) = 6.02/1683.5 = 0.00358
✓ Kp = 3.58x10^-3
Example 2
CO+H2O to CO2+H2

delta-n = 2-2 = 0. Kc=Kp (always when delta-n = 0).

  • Kp = Kc(RT)^0 = Kc x 1 = Kc
  • Kp = Kc for all temperatures
✓ Kp = Kc when delta-n = 0
Example 3
H2O(g) Decomposition

2H2O(g) to 2H2+O2. delta-n = 3-2 = +1. Kp = 1.00x10^-10 at 1000 K. Find Kc.

  • Kc = Kp/(RT)^1 = 1.00x10^-10/(0.08206x1000)
  • Kc = 1.00x10^-10/82.06 = 1.22x10^-12
✓ Kc = 1.22x10^-12

Real-World Applications

🏭
Gas-Phase Reactions
Kp is natural for gas-phase equilibria; Kc for solution reactions. Must convert between when needed.
📊
Thermodynamics
Standard Gibbs energy uses Kp: dG-deg = -RT ln Kp (for gas-phase reactions).
🧪
Physical Chemistry
Understanding the Kp/Kc relationship deepens knowledge of ideal gas behavior.
⚗️
Atmospheric Chemistry
Gas-phase equilibria (ozone, NOx) are described using Kp in pressure units.

Common Mistakes to Avoid

⚠️
Calculate delta-n from balanced equation

delta-n = moles of gaseous products - moles of gaseous reactants. Ignore solids and liquids.

⚠️
R must match pressure units

R=0.08206 L-atm/mol-K when Kp uses atm. R=8.314 J/mol-K when using Pa. Keep units consistent.

⚠️
When delta-n = 0, Kp = Kc

This is a useful check: for CO+H2O to CO2+H2, delta-n=0, so Kp always equals Kc.

Frequently Asked Questions

Why are there two forms of equilibrium constant?
Kc uses molar concentrations (mol/L); Kp uses partial pressures (atm). Both are valid; the relationship is Kp = Kc(RT)^delta-n.
Which should I use?
Kp is more convenient for gas-phase reactions. Kc for reactions in solution. Both give the same equilibrium position.
What is the standard state for Kp?
Kp uses pressures relative to 1 atm standard. So Kp is dimensionless when written as p_i/p-deg.
How does Kp relate to dG?
For gas-phase: dG-deg = -RT ln Kp. For solution: dG-deg = -RT ln Kc. They differ when delta-n is not zero.
What if some species are not gases?
Only gaseous species appear in Kp. Pure solids and liquids, and dissolved species, appear in Kc but not Kp.

Related Chemistry Calculators

Formula Explorer connections

Interpretation: This formula describes how reactants, products, ions or phases distribute when opposing processes reach equilibrium. Assumption: Use equilibrium rather than initial concentrations, correct stoichiometric exponents, and the specified temperature; activities may replace concentrations in nonideal systems.

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