Gibbs Free Energy Calculator
Calculate Gibbs free energy change using delta G = delta H - T*delta S. Determine if reactions are spontaneous, non-spontaneous, or at equilibrium at any temperature.
Formula & Reference
| Variable | Symbol | Formula | Units |
|---|---|---|---|
| Gibbs Free Energy Calculator | See formula | ΔG = ΔH - TΔS | kJ/mol |
Step-by-Step Examples
ΔH=-890.3 kJ/mol, ΔS=-242.8 J/mol·K, T=298 K.
- ΔG = -890.3 - (298×-242.8/1000)
- ΔG = -890.3 - (-72.35) = -817.9 kJ/mol
ΔH=+6.01 kJ/mol, ΔS=+22.0 J/mol·K at 298 K.
- ΔG = 6.01 - 298×0.0220 = 6.01 - 6.56 = -0.55 kJ/mol
- Spontaneous at 298 K (ice melts above 273 K)
ΔH=+40.7 kJ/mol (vaporization), ΔS=+109 J/mol·K. Find T where ΔG=0.
- ΔG = 0 when T = ΔH/ΔS = 40700/109 = 373 K
- 373 K = 100°C (boiling point of water)
Real-World Applications
Common Mistakes to Avoid
Common error: ΔS is in J/mol·K but ΔH is in kJ/mol. Divide ΔS by 1000 when subtracting: TΔS in kJ.
Thermodynamically spontaneous (ΔG < 0) means the reaction is favorable, not that it is fast. Kinetics (activation energy) controls rate.
Always use Kelvin for T. 25°C = 298.15 K. Celsius gives wrong ΔG values.
Frequently Asked Questions
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Formula Explorer connections
Interpretation: ΔG balances enthalpy against the temperature-weighted entropy change. Negative ΔG is thermodynamically favorable, zero marks equilibrium, and positive ΔG is unfavorable under the stated conditions. Assumption: ΔH and ΔS must use compatible units and temperature must be kelvin; spontaneity does not imply a fast reaction.