Young's Modulus Calculator
Calculate Young's modulus, deformation, or force using E = σ/ε = F·L₀/(A·ΔL).
E values (GPa): Steel=200, Al=70, Copper=120, Glass=70, Wood=5–15, Rubber=0.001–0.1, Bone=15–25
What Is Young's Modulus?
Young's modulus (E) is the ratio of tensile/compressive stress to strain within the elastic limit: E = σ/ε = F·L₀/(A·ΔL). It measures material stiffness — how much force per unit cross-section is needed per unit fractional deformation. Steel (E = 200 GPa) is 2.86× stiffer than aluminum (70 GPa) for the same geometry.
The relationship can be rearranged to find deformation: ΔL = F·L₀/(A·E). A 1 m steel rod (A = 1 cm² = 10⁻⁴ m²) under 20,000 N: ΔL = 20,000×1/(10⁻⁴×200×10⁹) = 10⁻³ m = 1 mm. This calculation is fundamental to structural design — ensuring deflections remain within acceptable limits.
Young's modulus is a fundamental material constant that determines the natural frequency of vibrations (ω ∝ √(E/ρ)), wave speed in the material (v = √(E/ρ)), and the buckling load of columns (Euler buckling: P_cr = π²EI/L²). Higher E materials are used in precision instruments and stiff structures.
E can be measured statically (from load-deformation curves) or dynamically (from resonant frequency of a test bar). Dynamic measurements tend to give slightly higher values. E decreases with temperature and approaches zero at the melting point. For composite materials, effective E depends on fiber orientation and volume fraction (rule of mixtures).
Formula Reference Table
| Solve For | Formula | Notes |
|---|---|---|
| Young's modulus | E = σ/ε = F·L₀/(A·ΔL) | Pa (GPa for most solids) |
| Deformation | ΔL = F·L₀/(A·E) | m |
| Force | F = E·A·ΔL/L₀ | N |
| Stress | σ = E·ε | Pa |
| Axial spring constant | k = E·A/L₀ | N/m (stiffness of a bar) |
| Wave speed in rod | v = √(E/ρ) | ρ = density; m/s |
3 Worked Examples
Steel rod: L₀ = 0.5 m, d = 20 mm, F = 100 kN, ΔL = 0.159 mm.
- A = π×(0.01)² = 3.14×10⁻⁴ m²
- σ = F/A = 10⁵/3.14×10⁻⁴ = 318 MPa
- ε = ΔL/L₀ = 0.000159/0.5 = 3.18×10⁻⁴
- E = σ/ε = 318×10⁶/3.18×10⁻⁴ = 200 GPa ✓
Steel I-beam: effective E×I = 800,000 N·m² (combined). Length 10 m, load 50 kN at midspan.
- Simply supported beam: δ = FL³/(48EI) = 50,000×1000/(48×800,000) = 50,000,000/38,400,000 = 1.30 mm
- Acceptable for most designs (L/deflection = 10,000/1.3 = 7,700 → well above L/360 minimum)
Wire: L₀ = 1.2 m, d = 1 mm, F = 800 N, ΔL = 1.7 mm.
- A = π×(0.0005)² = 7.854×10⁻⁷ m²
- E = F×L₀/(A×ΔL) = 800×1.2/(7.854×10⁻⁷×0.0017)
- E = 960/(1.335×10⁻⁹) = 71.9 GPa — aluminum!
Real-World Applications
Common Mistakes to Avoid
ΔL = FL₀/(AE) is for axial (tensile/compressive) deformation only. Bending deflection uses different formulas depending on loading and boundary conditions.
E = 200 GPa = 200×10⁹ Pa. If using E = 200 in the formula (without ×10⁹), ΔL = FL₀/(AE) gives deformation 10⁹× too large.
Circular cross-section: A = π(d/2)² = πd²/4. Diameter 20 mm = 0.02 m → A = π×(0.01)² = 3.14×10⁻⁴ m². Don't use radius where diameter is given.
E = σ/ε only in the elastic region. Above yield strength, the material deforms plastically — E no longer applies.
Wood, composite materials, and crystals have different E in different directions. Always specify the direction (e.g., E_parallel_to_grain for wood).
Frequently Asked Questions
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Interpretation: This engineering-physics relationship connects load, material property, geometry, deformation or system response. Assumption: Confirm material linearity, geometry, support conditions and safety convention. Small deformation, elastic behavior and ideal loading are common assumptions.