Orbital Energy Calculator
The total orbital energy of a two-body system is negative for bound orbits and zero for escape trajectories. Energy depends on the semi-major axis, not on eccentricity.
Formula & Reference
| Variable | Symbol | Formula | Units |
|---|---|---|---|
| Orbital Energy | E | E = −GMm/(2r) | J |
| Escape Condition | E = 0 | r = ∞ (parabolic trajectory) | — |
| Virial Theorem | — | KE = −E, PE = 2E | — |
| Binding Energy | — | −E = GMm/(2a) | J |
Step-by-Step Examples
M=5.972e24 kg (Earth), m=420,000 kg (ISS), r=6.771e6 m.
- E = -6.674e-11 * 5.972e24 * 420000 / (2*6.771e6)
- E = -1.237e16 J = -12.37 PJ
r=42,164 km = 4.2164e7 m, m=5000 kg satellite.
- E = -6.674e-11*5.972e24*5000/(2*4.2164e7)
- E = -2.364e10 J = -23.64 GJ
Compare two orbital energies to find delta-E needed.
- E(LEO,r=6.6e6m) - E(GEO,r=4.2e7m)
- = -G*M*m/2 * (1/r_LEO - 1/r_GEO)
Real-World Applications
Common Mistakes to Avoid
E < 0: bound (circular or elliptical orbit). E = 0: escape parabolic. E > 0: hyperbolic flyby. Always negative for stable orbits.
For elliptical orbits, replace r with semi-major axis a. Energy depends on a, not eccentricity.
Kinetic energy = magnitude of total energy. Potential energy = twice total energy. Important for stable bound systems.
Frequently Asked Questions
Related Physics Calculators
Formula Explorer connections
Interpretation: This relationship connects motion, force, momentum, work or energy in a mechanical system. Assumption: Choose a consistent reference direction and unit system. The model may assume constant acceleration, rigid bodies, negligible losses or an isolated system.