Momentum Calculator
Calculate momentum, mass, or velocity using p = mv. Supports all common unit conversions with impulse reference.
What Is Momentum?
Momentum is a measure of the quantity of motion possessed by an object. Defined as p = mv (mass × velocity), it captures both how heavy an object is and how fast it moves. The SI unit is kg·m/s (equivalently, N·s — newtons times seconds). Momentum is a vector: it has direction as well as magnitude, and opposing momenta can cancel.
The most powerful application of momentum is the law of conservation of momentum: in a closed system with no external forces, the total momentum remains constant. This holds regardless of whether the collision is elastic (kinetic energy preserved, like billiard balls) or inelastic (energy lost to deformation, like a car crash). Before any collision: Σp_initial = Σp_final.
Closely related is impulse (J = FΔt = Δp): the product of force and the time over which it acts equals the change in momentum. This explains why airbags and crumple zones save lives — they extend the collision time (Δt), reducing the peak force even when the total momentum change is identical. A 70 kg person stopping from 30 m/s to 0 experiences the same Δp = 2,100 kg·m/s whether the stop takes 0.05 s (F = 42,000 N — likely fatal) or 0.5 s (F = 4,200 N — survivable).
Momentum is also fundamental to Newton's second law in its most general form: F_net = dp/dt — the net force equals the rate of change of momentum. For constant mass, this reduces to F = ma, but the momentum form applies even when mass changes (rockets expelling fuel, conveyor belts accumulating material).
Formula Reference Table
| Solve For | Formula | Notes |
|---|---|---|
| Momentum (p) | p = m · v | Units: kg·m/s or N·s |
| Mass (m) | m = p / v | v must be non-zero |
| Velocity (v) | v = p / m | m must be non-zero |
| Impulse (J) | J = F · Δt = Δp | Change in momentum |
| Conservation | m₁v₁ + m₂v₂ = m₁v₁' + m₂v₂' | Before = after collision |
| Newton's 2nd (general) | F = Δp / Δt | Net force = rate of change of p |
3 Worked Examples
A 1,500 kg car travels at 100 km/h. What is its momentum?
- Convert: v = 100 ÷ 3.6 = 27.78 m/s
- Apply: p = m × v = 1,500 × 27.78 = 41,667 kg·m/s
- Compare: An 80 kg sprinter at 10 m/s has p = 800 kg·m/s — 52× less
A 75 kg driver decelerates from 60 km/h to rest. Compare crash (0.05 s) vs airbag (0.3 s).
- Δp: 75 × (60/3.6) = 75 × 16.67 = 1,250 kg·m/s
- Force without airbag: F = Δp/Δt = 1,250/0.05 = 25,000 N (≈ 34× body weight)
- Force with airbag: F = 1,250/0.3 = 4,167 N (≈ 5.7× body weight — survivable)
A 2 kg ball at 5 m/s hits a stationary 3 kg ball and sticks to it. Find final velocity.
- Before: p_total = 2 × 5 + 3 × 0 = 10 kg·m/s
- After (stick together): p_total = (2 + 3) × v_f = 5v_f
- Conservation: 5v_f = 10 → v_f = 2 m/s
Real-World Applications
Common Mistakes to Avoid
Both involve mass and velocity, but KE = ½mv² while p = mv. They have different units (J vs kg·m/s) and behave differently: doubling speed doubles momentum but quadruples kinetic energy. Never interchange them.
Momentum is a vector. If object A moves right (+) and object B moves left (−), their total momentum is p_A − p_B. Dropping signs gives wrong answers in collision problems, especially for head-on scenarios.
Conservation of momentum requires zero net external force. A ball rolling along the floor is not a closed system (friction is external). Two colliding billiard balls on a frictionless surface are — but include both balls in the system.
Impulse J = FΔt is a change in momentum (Δp), not momentum itself. J = 500 N·s means the object's momentum changed by 500 kg·m/s, not that it now has 500 kg·m/s of momentum — it may have had momentum before.
p = mv requires mass in kg. Using grams (÷1000) or pounds (×0.4536) without conversion gives momentum off by factors of 1,000 or 2.2. Always convert to kg before calculating.
Frequently Asked Questions
Related Physics Calculators
Formula Explorer connections
Interpretation: This relationship connects motion, force, momentum, work or energy in a mechanical system. Assumption: Choose a consistent reference direction and unit system. The model may assume constant acceleration, rigid bodies, negligible losses or an isolated system.