Electrical Power Calculator
Calculate electrical power using P = VI = I²R = V²/R. Find any variable given two others.
What Is Electrical Power?
Electrical power (P) is the rate of energy transfer in an electric circuit, measured in watts (W = J/s). Three equivalent formulas relate power to voltage, current, and resistance: P = VI = I²R = V²/R. These are all derived from Ohm's Law (V = IR) — any one can be computed from any two of V, I, and R.
The P = I²R form is particularly important for understanding energy loss in resistors (Joule heating). It shows that power loss scales with the square of current — doubling current quadruples power dissipated as heat. This is why power transmission uses high voltage (low current) to minimize I²R losses over long distances.
Power determines component selection in circuits. A resistor rated at ¼ W in a circuit dissipating 1 W will overheat and fail. Engineers calculate P = I²R for each component and select components with adequate power ratings (typically 2× the calculated value as a safety margin).
Electrical power units: 1 W = 1 J/s. Household: kW (kilowatts). Power plants: MW to GW. The kilowatt-hour (kWh) is the energy unit: 1 kWh = 3.6 MJ. A 1 kW heater running for 2 hours consumes 2 kWh.
Formula Reference Table
| Solve For | Formula | Notes |
|---|---|---|
| Power | P = V·I = I²R = V²/R | Watts (W) |
| From voltage and current | P = V·I | Direct calculation |
| From current and resistance | P = I²·R | Joule heating formula |
| From voltage and resistance | P = V²/R | Common for fixed-V circuits |
| Energy over time | E = P·t | Joules = Watts × seconds |
| Efficiency | η = P_out/P_in × 100% | Percentage |
3 Worked Examples
120 V, 60 W bulb: I = P/V = 60/120 = 0.5 A; R = V/I = 240 Ω. LED equivalent (8 W): I = 0.067 A, R = 1,800 Ω.
- Bulb: P = VI = 120 × 0.5 = 60 W (≈3 W visible, 57 W heat)
- LED: P = 8 W (≈6 W visible, 2 W heat)
- LED is 7.5× more power-efficient for same light output
2,500 W kettle on 240 V mains. Find current and element resistance.
- I = P/V = 2500/240 = 10.4 A
- R = V/I = 240/10.4 = 23.1 Ω
- Or R = V²/P = 57,600/2,500 = 23.0 Ω ✓
100 Ω resistor in circuit with 20 V across it. Power dissipated?
- P = V²/R = 400/100 = 4 W
- Standard 100 Ω resistors: 1/4 W, 1/2 W, 1 W, 2 W
- Must use ≥ 5 W rated resistor (safety margin 2×: ≥ 8 W)
Real-World Applications
Common Mistakes to Avoid
The three power formulas use multiplication, not division for the I²R and V²/R forms. P = I²R (multiply); P = V²/R (divide by R). Double-check: larger R → more power dissipated per amp (I²R), but less power for same voltage (V²/R — dividing by larger R).
AC average power uses RMS values: P = V_rms × I_rms × cos(φ). For a purely resistive load (φ=0): P = V_rms × I_rms. V_rms = V_peak/√2 for sine wave. Using peak values gives P that is 2× too high.
Power (W) is rate; energy (J or kWh) is total. A 1000 W device consumes 1 kWh if run for 1 hour — or 0.5 kWh if run for 30 min.
For inductive/capacitive loads: P_true = V×I×cos(φ). The apparent power S = VI (VA); power factor PF = P/S. Motors and fluorescent lights have PF < 1.
Always use a resistor rated for more than calculated P. Minimum factor of 1.5–2×. P_calculated = 1 W → minimum resistor rating = 2 W. The standard series is 1/8, 1/4, 1/2, 1, 2, 5, 10, 25 W.
Frequently Asked Questions
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Interpretation: This relationship connects motion, force, momentum, work or energy in a mechanical system. Assumption: Choose a consistent reference direction and unit system. The model may assume constant acceleration, rigid bodies, negligible losses or an isolated system.