pH of Salt Solution Calculator
Calculate pH of salt solutions formed from acid-base reactions. Determine if a salt gives acidic, basic, or neutral pH using Ka and Kb of parent acid and base.
Formula & Reference
| Variable | Symbol | Formula | Units |
|---|---|---|---|
| pH of Salt Solution Calculator | — | pH from Kh = Kw/Ka or Kw/Kb | pH |
Step-by-Step Examples
0.100 M NaCH3COO. Ka(acetic acid)=1.8x10^-5.
- Kh = Kw/Ka = 10^-14/1.8x10^-5 = 5.56x10^-10
- [OH-] = sqrt(Kh*C) = sqrt(5.56x10^-10 x 0.100)
- = sqrt(5.56x10^-11) = 7.46x10^-6
- pOH = 5.13, pH = 14-5.13 = 8.87
0.100 M NH4Cl. Kb(NH3)=1.8x10^-5, Ka(NH4+)=Kw/Kb=5.6x10^-10.
- Kh = Ka(NH4+) = 5.6x10^-10
- [H+] = sqrt(5.6x10^-10 x 0.100) = 7.48x10^-6
- pH = -log(7.48x10^-6) = 5.13
NaCl: Na+ from strong base, Cl- from strong acid. Neither hydrolyzes.
- pH = 7.00 at 25 C
- Strong acid + strong base salts are always neutral
Real-World Applications
Common Mistakes to Avoid
NaCH3COO comes from NaOH (strong) + CH3COOH (weak). Weak acid parent: anion hydrolyzes to give basic solution.
For sodium acetate: Ka = 1.8x10^-5 is Ka of acetic acid. Kh of acetate anion = Kw/Ka.
NaCl, KNO3, LiClO4: both ions from strong acid/base; no hydrolysis; pH = 7.
Frequently Asked Questions
Related Chemistry Calculators
Formula Explorer connections
Interpretation: This relationship connects hydrogen-ion activity, dissociation, conjugate ratios or titration stoichiometry to acid–base behavior. Assumption: Concentration approximates activity mainly in dilute solutions. Temperature, ionic strength, acid strength and equilibrium approximations affect accuracy.