Nuclear Binding Energy Calculator

Calculate nuclear binding energy and binding energy per nucleon for any isotope.

Fe-56: A=56
Fe: Z=26
From isotope tables
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Where the Mass Goes

A nucleus weighs less than the sum of its separate protons and neutrons. That missing mass — the mass defect — was converted to energy when the nucleus formed, and it is exactly the energy needed to pull it apart again.

Δm = Zmp + (A−Z)mn − M     BE = Δm × 931.5 MeV/u

The conversion factor 931.5 MeV per atomic mass unit comes directly from E = mc². A mass defect of just 0.0024 u — about one part in a thousand — corresponds to 2.2 MeV, which is roughly a million times the energy of a chemical bond.

Why Iron Sits at the Peak

Binding energy per nucleon is what matters for stability, and it peaks near iron-56 at about 8.8 MeV per nucleon. The curve rises steeply to that point, then declines slowly.

NucleusBE/A (MeV)Consequence
H-2 (deuterium)1.11Very loosely bound
He-47.07Unusually stable for its size
Fe-568.79Near the maximum
U-2357.59Below peak — fission releases energy

The shape explains both nuclear energy routes. Fusion of light nuclei climbs the steep left side, releasing large energy per nucleon. Fission of heavy nuclei moves right to left down the shallow right side, releasing less per nucleon but from far more massive nuclei. Iron is the endpoint of both — which is why stellar fusion halts there and why iron is so abundant in the universe.

Two competing effects produce the peak. The strong force acts only between neighbouring nucleons, so binding per nucleon saturates. Electrostatic repulsion between protons acts across the whole nucleus and grows with Z², eventually dominating.

Worked Examples

Example 1: Fe-56: A=56, Z=26, M=55.9349u
Δm=56×mp+30×mn-55.9349
Result: BE=492.3 MeV, BE/A=8.79 MeV
Most stable nucleus — peak of binding energy curve
Example 2: Deuterium: A=2, Z=1, M=2.01410u
Δm=mp+mn-2.01410=0.00239u
Result: BE=2.23 MeV, BE/A=1.11 MeV
Weakly bound — easy to fuse (low Coulomb barrier)
Example 3: Why He-4 is anomalously stable
BE/A = 7.07 MeV at A = 4, well above its neighbours
Result: Explains alpha decay
The unusual stability of the He-4 nucleus is why heavy nuclei preferentially emit alpha particles rather than individual nucleons.
Example 4: Fusion versus fission energy
D+T fusion gives 17.6 MeV from 5 nucleons; U-235 fission gives ~200 MeV from 236
Result: 3.5 versus 0.85 MeV per nucleon
Fusion releases about four times more energy per nucleon, which is why it is so attractive despite the engineering difficulty.

Common Mistakes

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Using the nuclear mass instead of the atomic mass

Tabulated atomic masses include the electrons. Either use the proton mass and atomic mass consistently, or subtract the electron masses — mixing conventions introduces a small but systematic error.

⚠️
Confusing total binding energy with binding energy per nucleon

Uranium has far more total binding energy than iron, but less per nucleon. Stability is governed by the per-nucleon figure.

⚠️
Forgetting to subtract Z from A for neutrons

The neutron count is A minus Z. Using A for both particle counts roughly doubles the calculated mass defect.

⚠️
Assuming heavier always means more stable

Beyond iron, binding energy per nucleon falls. That is precisely why heavy nuclei can release energy by splitting.

Frequently Asked Questions

Why does binding energy peak at Fe?
Fusion of elements lighter than Fe releases energy (BE/A increases). Fission of elements heavier than Fe releases energy (BE/A increases toward Fe). Fe-56 is the endpoint — most energetically stable nucleus. Stars 'burn' fuel until reaching Fe.
Liquid drop model?
BE ≈ aV×A - aS×A^(2/3) - aC×Z²/A^(1/3) - aA×(N-Z)²/A ± δ. Volume, surface, Coulomb, asymmetry, and pairing terms. Explains the shape of BE/A curve and allows mass predictions for unknown isotopes.
What is mass defect?
The difference between the summed masses of free nucleons and the actual nuclear mass. It was converted to binding energy when the nucleus formed.
Why does binding energy peak at iron?
Strong force binding saturates because it acts only between neighbours, while proton repulsion grows with Z² across the whole nucleus. The balance optimises near A = 56.
Why does fusion release more energy per nucleon than fission?
Because the binding energy curve rises steeply on the light side and falls gently on the heavy side. Climbing the steep side releases more per nucleon.
What does 931.5 MeV/u represent?
The energy equivalent of one atomic mass unit from E = mc². It converts mass defect directly into binding energy.

Formula Explorer connections

Interpretation: This relationship connects isotopic composition, decay, radiation, mass defect or nuclear energy to a measurable quantity. Assumption: Use the correct nuclide, decay constant, branching behavior and time units. Radiation estimates also depend on geometry, shielding and detector response.

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