Antoine Equation Calculator

Calculate vapor pressure at any temperature using Antoine equation coefficients.

Please check your inputs and try again.

Why Vapour Pressure Rises Non-Linearly

Vapour pressure increases steeply and non-linearly with temperature, because the fraction of molecules with enough energy to escape follows a Boltzmann distribution. The Antoine equation is an empirical fit that captures this over a limited range.

log10P = A − B/(C + T)

A, B and C are fitted constants with no direct physical meaning, unlike the Clausius–Clapeyron equation whose slope gives the enthalpy of vaporisation. The trade-off is accuracy: Antoine fits real data better over its stated range because the C term corrects for the temperature dependence of ΔHvap.

Point of careDetail
Units of PUsually mmHg, sometimes kPa or bar — constants differ
Units of TUsually °C, sometimes K — constants differ
Log baseUsually base 10, occasionally natural log
Valid rangeAlways stated with the constants

Because four conventions vary independently, Antoine constants from different sources are frequently incompatible. A set fitted for kPa and kelvin used with mmHg and Celsius produces nonsense. Always check what the source specifies.

Boiling Point and Altitude

Setting P equal to ambient pressure and solving for T gives the boiling point. At 2,000 m the atmosphere is about 79 kPa, so water boils near 93°C — which is why cooking times lengthen at altitude and pressure cookers are used to reverse the effect.

Extrapolating outside the fitted range is the main hazard. The equation has no physical basis, so it can produce plausible-looking but badly wrong values well beyond where it was fitted. Two constant sets are commonly published for water because no single fit covers both low and high temperature well.

Worked Examples

Example 1: Water at 25°C
log P = 8.07131-1730.63/(25+233.426)
Result: P=23.8 mmHg = 3.17 kPa
Matches steam tables: 3.169 kPa at 25°C ✓
Example 2: Ethanol at 20°C
log P = 8.1122-1592.864/(20+226.184)
Result: P=44.0 mmHg = 5.87 kPa
Relatively volatile: flammable at room temp
Example 3: Boiling at altitude
Ambient pressure 79 kPa (about 2,000 m)
Result: Water boils near 93°C
Solving Antoine for T where P equals ambient. Lower boiling temperature means slower cooking, which pressure cookers counteract by raising the pressure.
Example 4: The steepness of the curve
Water vapour pressure at 25°C versus 100°C
Result: 23.7 mmHg versus 760 mmHg
A 32-fold increase over 75 degrees. The exponential form is why modest heating causes such large changes in evaporation rate.

Common Mistakes

⚠️
Mixing constant sets with the wrong units

Constants are fitted for a specific pressure unit, temperature unit and log base. Using a mismatched set produces answers that can be wrong by orders of magnitude.

⚠️
Extrapolating beyond the valid range

Antoine is empirical with no physical basis outside its fitted interval. Extrapolation gives plausible-looking but unreliable results.

⚠️
Using a single constant set for water across all temperatures

Water usually requires two sets, one for roughly 1–100°C and another above. Using the low-temperature set at 150°C is a common error.

⚠️
Confusing vapour pressure with partial pressure

Vapour pressure is the equilibrium pressure of the pure substance at that temperature. Partial pressure in a mixture depends on composition through Raoult's law.

Frequently Asked Questions

Antoine equation form?
log₁₀(P) = A - B/(T+C) with P in mmHg and T in °C (common form). Also used with Pa, bar, K — check coefficient source. NIST WebBook: authoritative Antoine coefficients with validity range.
Extrapolation danger?
Antoine equation is empirical fit, only valid within specified T range. Extrapolating beyond range gives unreliable results. For wide T range, use cubic spline or multi-parameter equations (DIPPR, Wagner equation).
What do the Antoine constants mean?
They are empirical fitting parameters with no direct physical interpretation, unlike the Clausius–Clapeyron slope which gives enthalpy of vaporisation.
Why do published constants differ?
Because they depend on pressure units, temperature units and log base, all of which vary between sources. Always check the stated conventions.
Can I extrapolate outside the valid range?
No. The equation is purely empirical, so extrapolation produces plausible-looking but unreliable values. Use constants fitted for your range.
How do I find boiling point from the equation?
Set P equal to the ambient pressure and solve for T. At 79 kPa, corresponding to roughly 2,000 m altitude, water boils near 93°C.

Formula Explorer connections

Interpretation: This relationship connects pressure, volume, temperature, amount or phase composition for gases and volatile mixtures. Assumption: Use absolute temperature and compatible pressure-volume units. Ideal behavior weakens at high pressure, low temperature, strong intermolecular attraction or near phase change.

Avogadro's Law Calculator →Combined Gas Law Calculator →Boyle's Law Calculator →Chemistry Formula Explorer →