ESS Game Theory Calculator

Calculate fitness payoffs and evolutionary stable strategies for hawk-dove and other games.

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Why the Equilibrium Sits Where It Does

An evolutionarily stable strategy is one that, once common, cannot be invaded by any rare alternative. In the Hawk–Dove game the answer depends entirely on whether the cost of fighting exceeds the value of the resource.

ConditionESSInterpretation
V > CAll HawkResource worth more than injury risk
V < CMixed, p = V/CNeither pure strategy is stable
p*(Hawk) = V/C   when V < C

The mixed equilibrium is frequency-dependent, and that is what makes it stable. When Hawks are rare they mostly meet Doves and do well, so their frequency rises. When Hawks are common they mostly meet each other and pay the injury cost, so their frequency falls. The population settles where the two payoffs are equal.

Note the equilibrium can be reached two ways: a population of individuals each playing Hawk with probability V/C, or a stable polymorphism of pure Hawks and pure Doves in that ratio. The game theory cannot distinguish them.

Why Real Contests Are Rarely Lethal

The model predicts that as injury cost rises relative to resource value, the equilibrium proportion of escalated fighting falls. This matches observation: most animal contests are settled by display rather than combat.

RefinementWhat it adds
Bourgeois strategyRespect ownership — often an ESS itself
Assessor strategyFight only if larger than the opponent
War of attritionContests over persistence rather than injury
Asymmetric contestsResource value differs between individuals

The Bourgeois strategy — play Hawk when the owner, Dove when the intruder — is stable and needs no assessment of fighting ability, only a convention. Territorial residency effects in butterflies and spiders match this closely.

The model's limits are worth stating: it assumes fitness payoffs are additive and contests are pairwise and independent, and it ignores kin selection, learning and reputation, all of which shape real animal conflict substantially.

Worked Examples

Example 1: V=6, C=10 (cost exceeds value): ESS = V/C = 0.6
60% Hawks at equilibrium
Result: ESS < 1: mixed strategy (polymorphism)
Mixed ESS applies only when V < C
Example 2: V=10, C=4: ESS = 10/4 = 2.5 > 1
ESS = 1 (all Hawks)
Result: When V>C: Hawks always win, all become Hawks
Territory without serious injury: expect more aggression
Example 3: Why the mixed point is stable
Hawks rare, then Hawks common
Result: Frequency-dependent selection
Rare Hawks mostly meet Doves and prosper; common Hawks mostly meet each other and pay the cost. The frequency is pushed back toward V/C from either side.
Example 4: The Bourgeois convention
Play Hawk if owner, Dove if intruder
Result: Stable without any assessment
An arbitrary convention resolves the contest at no cost. Residency effects in territorial butterflies match this prediction closely.

Common Mistakes

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Applying p = V/C when V exceeds C

That formula only holds when cost exceeds value. When V > C the ESS is pure Hawk, and V/C would exceed 1 which is meaningless as a frequency.

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Confusing an ESS with a group optimum

An ESS is uninvadable, not efficient. The Hawk–Dove equilibrium has lower mean fitness than an all-Dove population would — which is precisely why all-Dove is unstable.

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Assuming a mixed ESS means mixed individuals

The same equilibrium arises from every individual randomising or from a stable polymorphism of pure types. Game theory cannot distinguish them.

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Treating payoffs as fixed

Resource value and injury cost vary with condition, hunger and ownership. Asymmetric versions of the game capture this and predict different outcomes.

Frequently Asked Questions

What is an ESS?
Evolutionary Stable Strategy: strategy that, when adopted by most of the population, cannot be invaded by a rare mutant. Not necessarily Nash equilibrium. Mixed ESS occurs when no pure strategy is stable.
Hawk-Dove in nature?
Explains animal contest behavior: ritualized displays instead of serious fights. When injury cost high (C) relative to resource value (V): animals evolve to assess, bluff, or escalate carefully. Badge-of-status signals resolve contests without fights.
What is an evolutionarily stable strategy?
One that cannot be invaded by any rare alternative strategy once it is common in the population.
When is the Hawk–Dove ESS mixed?
When the cost of injury exceeds the resource value. The equilibrium Hawk frequency is then V/C. When value exceeds cost, pure Hawk is stable.
Why is the mixed equilibrium stable?
Because payoffs are frequency-dependent. Rare Hawks do well against common Doves and common Hawks do badly against each other, restoring the balance.
Is an ESS the best outcome for the population?
No. It is uninvadable, not optimal. All-Dove would give higher mean fitness but is unstable because a single Hawk would prosper.